(9x+5)(2x^2-13x-7)=0

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Solution for (9x+5)(2x^2-13x-7)=0 equation:


Simplifying
(9x + 5)(2x2 + -13x + -7) = 0

Reorder the terms:
(5 + 9x)(2x2 + -13x + -7) = 0

Reorder the terms:
(5 + 9x)(-7 + -13x + 2x2) = 0

Multiply (5 + 9x) * (-7 + -13x + 2x2)
(5(-7 + -13x + 2x2) + 9x * (-7 + -13x + 2x2)) = 0
((-7 * 5 + -13x * 5 + 2x2 * 5) + 9x * (-7 + -13x + 2x2)) = 0
((-35 + -65x + 10x2) + 9x * (-7 + -13x + 2x2)) = 0
(-35 + -65x + 10x2 + (-7 * 9x + -13x * 9x + 2x2 * 9x)) = 0
(-35 + -65x + 10x2 + (-63x + -117x2 + 18x3)) = 0

Reorder the terms:
(-35 + -65x + -63x + 10x2 + -117x2 + 18x3) = 0

Combine like terms: -65x + -63x = -128x
(-35 + -128x + 10x2 + -117x2 + 18x3) = 0

Combine like terms: 10x2 + -117x2 = -107x2
(-35 + -128x + -107x2 + 18x3) = 0

Solving
-35 + -128x + -107x2 + 18x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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